C++で誘導電動機の同期速度を求める

Ns -> 1500

#define _USE_MATH_DEFINES
#include <iostream>
#include <math.h>

class IM {

public:
    std::string name = "";
    double r1 = 0.0;
    double r2 = 0.0;

    double x1 = 0.0;
    double x2 = 0.0;

    double s = 0.0;
    double V = 0.0;

    double I = 0.0;

    unsigned char p = 0.0;
    double f = 0.0;

    double P = 0.0;
    double T = 0.0;

    unsigned int N = 0.0;
    unsigned int Ns = 0.0;

    void show(void) {
        std::cout << "r1->" << r1 << std::endl;
        std::cout << "r2->" << r2 << std::endl;
        std::cout << "x1->" << x1 << std::endl;
        std::cout << "x2->" << x2 << std::endl;
        std::cout << "s->" << s << std::endl;
        std::cout << "V->" << V << std::endl;
        std::cout << "I->" << I << std::endl;
    }
    double syncspeed(IM motor) {
        return 120*motor.f / motor.p;
    }
    double torque(IM motor) {
        return motor.P / (2 * M_PI * motor.N / 60);
    }
    double current(IM motor) {
        double Z, R, X;
        R = motor.r1 + motor.r2 / motor.s;
        X = motor.x1 + motor.x2;

        Z = sqrt(std::pow(R, 2) + std::pow(X, 2));

        return motor.V / (sqrt(3) * Z);
    }
};

int main() {
    double P0;
    IM motor1;

    motor1.p = 4;
    motor1.f = 50;

    motor1.Ns = motor1.syncspeed(motor1);

    std::cout << "Ns -> " << motor1.Ns << std::endl;

    return 0;
}