C++で二次電流の一次変換値を求める

r1->0.1
r2->0.15
x1->0.3
x2->0.4
s->0.05
V->200
I->36.3336

#include <iostream>

#define pi 3.14

class IM{
public:
    std::string name = "";
    double r1 = 0.0;
    double r2 = 0.0;
 
    double x1 = 0.0;
    double x2 = 0.0;
    
    double s = 0.0;
    double V = 0.0;

    double I = 0.0;

    void show(void) {
        std::cout << "r1->" << r1 << std::endl;
        std::cout << "r2->" << r2 << std::endl;
        std::cout << "x1->" << x1 << std::endl;
        std::cout << "x2->" << x2 << std::endl;
        std::cout << "s->" << s << std::endl;
        std::cout << "V->" << V << std::endl;
        std::cout << "I->" << I << std::endl;
    }
};

double torque(double P, int N) {
    return P / (2 * pi * N / 60);
}

double current(IM motor) {
    double Z, R, X;
    R = motor.r1 + motor.r2 / motor.s;
    X = motor.x1 + motor.x2;

    Z = sqrt(std::pow(R, 2) + std::pow(X, 2));
 
    return motor.V / (sqrt(3) * Z);
}
int main() {
    double P0;
    IM motor1;

    motor1.r1 = 0.1;
    motor1.r2 = 0.15;

    motor1.x1 = 0.3;
    motor1.x2 = 0.4;

    motor1.s = 0.05;
    motor1.V = 200;

    
    motor1.I = current(motor1);
    
    motor1.show();

    return 0;
}